32x^2-64x+32=0

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Solution for 32x^2-64x+32=0 equation: 



32x^2-64x+32=0

a = 32; b = -64; c = +32;
Δ = b2-4ac
Δ = -642-4·32·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{64}{64}=1$

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